Question Detail

CHM 102 Practice Questions Objective Question

Question

Addition of HCl to 3-methyl-1-pentene gives two products. One of these is 2-chloro-3-methylpentane. What is the other product?
Options
A 1-Chloro-3-methylpentane
B 3-Chloro-3-methylpentane
Correct Answer
C 3-Chloro-2-methylpentane
D 2-Chloro-2-methylpentane
Correct Answer

Option B is the correct answer.

Detailed Explanation

Addition of HCl to 3-methyl-1-pentene (CH2=CH-CH(CH3)-CH2-CH3) involves a carbocation rearrangement. The initially formed carbocation rearranges via a 1,2-hydride shift to give a more stable tertiary carbocation, which then gives 3-chloro-3-methylpentane. The direct Markovnikov product is 2-chloro-3-methylpentane.

Hint

What is the rearranged product from HCl addition to 3-methyl-1-pentene?

Question Info