Question Detail
Question
A small object carrying a charge of 5 x 10-9 C experiences a downward force of 20 x 10-9 N when placed at a certain point in an electric field. What is the electric field at the point?
Correct Answer
Option C is the correct answer.
Detailed Explanation
The electric field (E) is defined as the force (F) per unit charge (Q). Therefore, E = F/Q.Given F = 20 x 10-9 N and Q = 5 x 10-9 C.E = (20 x 10-9 N) / (5 x 10-9 C) = 4 N/C.Thus, the electric field at the point is 4.00 N/C.
Hint
Remember the definition of electric field intensity: Force per unit charge.