Question Detail

PHY 102 Test Compilation PHY 102 11 Objective Question
Take CBT

Question

When a battery, a resistor, a switch, and an inductor form a circuit, and the switch is closed, the inductor acts to oppose the change in the current. How is the time constant of the inductor affected by doubling the resistance in the circuit?
Options
A The time constant would increase to four times its original value.
B The time constant would increase to twice its original value.
C The time constant would remain the same.
D The time constant would decrease to one-half its original value.
Correct Answer
Correct Answer

Option D is the correct answer.

Detailed Explanation

The time constant (τ) for an RL (Resistor-Inductor) circuit is given by the formula τ = L/R, where L is the inductance and R is the resistance.If the resistance (R) is doubled, the new resistance becomes 2R.The new time constant (τ') would be L/(2R).So, τ' = (1/2) * (L/R) = (1/2) * τ.Therefore, the time constant would decrease to one-half its original value.

Hint

Remember the formula for the time constant of an RL circuit.

Question Info

Course: PHY 102
Topic: Test Compilation PHY 102 11
Type: Objective
Difficulty: Not specified
Question 928 of 1819
Previous Course Details Next