Question Detail

PHY 102 Test Compilation PHY 102 11 Objective Question

Question

The power dissipated by a 72 Ω resistor connected to sinusoidal a.c. source is 24W, determine the peak-to-peak voltage across the resistor.
Options
A 117.5v
Correct Answer
B 58.8v
C 41.5v
D 235v
Correct Answer

Option A is the correct answer.

Detailed Explanation

Given Power (P) = 24 W and Resistance (R) = 72 Ω.1. Calculate the RMS voltage (Vrms): P = Vrms2 / R => Vrms2 = P * R = 24 W * 72 Ω = 1728 V2.Vrms = √1728 ≈ 41.569 V.2. Calculate the peak voltage (Vpeak): For a sinusoidal AC source, Vpeak = Vrms * √2.Vpeak = 41.569 V * √2 ≈ 41.569 V * 1.414 ≈ 58.78 V.3. Calculate the peak-to-peak voltage (Vp-p): Vp-p = 2 * Vpeak.Vp-p = 2 * 58.78 V ≈ 117.56 V.Rounding to one decimal place gives 117.5 V.

Hint

Recall the relationships between power, resistance, RMS voltage, peak voltage, and peak-to-peak voltage in an AC circuit.

Question Info