Question Detail

Electric flux (Φ) is given by Φ = E × A × cos(θ), where E is the electric field intensity, A is the area, and θ is the angle between the electric field vector and the normal to the surface.Given: E = 100 N/C. Radius r = 7 m, so Area A = πr2 = π(7 m)2 = 49π m2.The angle given is 60° to the surface, so the angle with the normal is θ = 90° - 60° = 30°.Φ = 100 N/C × 49π m2 × cos(30°)Φ = 100 × 49π × (√3 / 2) Nm2/CΦ = 50 × 49π × √3 Nm2/CΦ = 2450π√3 Nm2/C.Using π ≈ 3.14159, Φ ≈ 2450 × 3.14159 × 1.73205 ≈ 13333.6 Nm2/C.Now, let's check the options:Option C: 7700√3 ≈ 7700 × 1.73205 ≈ 13336.785 Nm2/C. This is a very close match.(Note: The original question has 'Nm²/CNm²/C' which is a typo in unit, it should be Nm²/C or Vm).