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PHY 102 Test Compilation PHY 102 14 Objective Question

Question

In a parallel-plate capacitor, the distance d between the plates is 3cm, the area of each plate is 15cm2, and the voltage across them is 5V. Calculate the capacitance. Take permittivity of free space to be ε0 = 8.854 × 10-12C/Nm2.
Options
A 3.33 x 10<sup>-13</sup> F
B 9.31 x 10<sup>-11</sup> F
C 4.43 x 10<sup>-13</sup> F
Correct Answer
D 1.29 x 10<sup>-12</sup> F
Correct Answer

Option C is the correct answer.

Detailed Explanation

The capacitance of a parallel-plate capacitor is given by the formula C = ε0A/d, where C is capacitance, ε0 is the permittivity of free space, A is the area of one plate, and d is the distance between the plates. Given A = 15 cm2 = 15 × 10-4 m2, d = 3 cm = 0.03 m, and ε0 = 8.854 × 10-12 F/m. Plugging in the values: C = (8.854 × 10-12 F/m) × (15 × 10-4 m2) / (0.03 m) = 4.427 × 10-13 F, which is approximately 4.43 × 10-13 F.

Hint

Convert all units to SI (meters, square meters) before calculation and use C = ε0A/d.

Question Info