Question Detail
Question
A straight wire of length 0.20 m moves at a speed of 3.0 m s-1 90° to magnetic field of flux density 0.10 T. Find the induced e.m.f
Correct Answer
Option B is the correct answer.
Detailed Explanation
The induced electromotive force (emf) in a straight conductor moving in a uniform magnetic field is given by the formula for motional emf:ε = B L v sin(θ)Where:B = Magnetic flux density = 0.10 TL = Length of the wire = 0.20 mv = Speed of the wire = 3.0 m/sθ = Angle between the velocity vector and the magnetic field vector = 90°Substitute the values into the formula:ε = (0.10 T) * (0.20 m) * (3.0 m/s) * sin(90°)Since sin(90°) = 1:ε = 0.10 * 0.20 * 3.0 * 1ε = 0.06 V
Hint
Use the formula for motional EMF: ε = B L v sin(θ), where θ is the angle between the velocity and magnetic field vectors.