Question Detail

PHY 102 Test Compilation PHY 102 19 Objective Question
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Question

Determine the force on an electron of charge 1.6×10⁻¹⁹C which is placed in a uniform electric field of 120,000V/m.
Options
A 0N
B 1.92 × 10⁻¹⁴N
Correct Answer
C 1.92 × 10⁻¹⁴N (opposite direction)
D 1.92 × 10⁻¹²N
Correct Answer

Option B is the correct answer.

Detailed Explanation

F = qE = (1.6×10⁻¹⁹)(120,000) = 1.92×10⁻¹⁴N.

Hint

Apply F = qE directly using the electron's charge magnitude.

Question Info

Course: PHY 102
Topic: Test Compilation PHY 102 19
Type: Objective
Difficulty: Not specified
Question 1196 of 1819
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