Question Detail
Question
Two charges with equal magnitude exert an attractive force of 4.0×10^-4 N on each other. If the magnitude of each charge is 2.0 microcoulomb, how far apart are the charges?
Correct Answer
Option B is the correct answer.
Detailed Explanation
F = kq²/r² => r = √(kq²/F) = √((9×10^9 × (2×10^-6)²) / (4×10^-4)) ≈ 9.5m.
Hint
Solve Coulomb's law for distance.