Question Detail
Question
What is the resonant frequency of a circuit of negligible resistance, inductance of 40mH and capacitance 0.25μF?
Correct Answer
Option B is the correct answer.
Detailed Explanation
f = 1/(2π√(LC)) = 1/(2π√(0.04 × 0.25×10^-6)) = 10⁴/(2π) = 5000/π Hz.
Hint
Resonant frequency f = 1/(2π√LC).