Question Detail
Question
Light of wavelength 580 nm is incident on a slit of width 0.300 mm. An observing screen is placed 2.00 m from the slit. Find the position of the first order dark fringe from the center of the screen.
Correct Answer
Option C is the correct answer.
Detailed Explanation
For single-slit diffraction, the position of the first dark fringe (m=1) is given by y = (mλL)/a, where λ is the wavelength (580 nm = 580 × 10^-9 m), L is the distance to the screen (2.00 m), and a is the slit width (0.300 mm = 0.300 × 10^-3 m). y = (1 × 580 × 10^-9 × 2.00) / (0.300 × 10^-3) = 1160 × 10^-9 / 0.300 × 10^-3 = 3.866 × 10^-3 m = 3.866 mm.
Hint
Use the formula for the position of dark fringes in single-slit diffraction: y = (mλL)/a, where m is the order (1 for first dark fringe).