Question Detail
Question
An atom changing from an energy state of -0.54 eV to an energy state of -0.85 eV will emit a photon whose energy is:
Correct Answer
Option A is the correct answer.
Detailed Explanation
When an atom transitions from a higher energy state to a lower energy state, it emits a photon with energy equal to the difference in energy levels. Photon energy = E_initial - E_final = -0.54 eV - (-0.85 eV) = 0.31 eV.
Hint
The energy of the emitted photon is the difference in energy between the two states: ΔE = E_initial - E_final.