Question Detail

PHY 104 PHY 104 Past Questions Objective Question

Question

Find the mass defect of ⁶³₂₈Cu if the actual mass of copper is 62.91367 u.
Options
A 6.73728 u
B 2.977889 u
C 0.59223 u
Correct Answer
D 1.99773 u
Correct Answer

Option C is the correct answer.

Detailed Explanation

Mass defect (Δm) = [Z(m_p + m_e) + (A-Z)m_n] - actual mass. For Copper-63, Z=29, A=63, A-Z=34. Using the given masses: m_p = 1.007276 u, m_e = 0.00054858 u, m_n = 1.008665 u. Calculated mass = 29(1.007276 + 0.00054858) + 34(1.008665) = 29(1.00782458) + 34(1.008665) = 29.22691282 + 34.29461 = 63.52152282 u. Mass defect = 63.52152282 - 62.91367 = 0.60785282 u. The closest option is 0.59223 u.

Hint

Mass defect is the difference between the sum of the masses of individual nucleons (protons and neutrons) and the actual mass of the nucleus. Use Δm = [Z(m_p + m_e) + (A-Z)m_n] - M_actual.

Question Info