Question Detail
Question
The Q-factor of a sonometer wire of frequency 600 Hz is 8000. What is the time for its energy to decay to 1/e of its initial value?
Correct Answer
Option B is the correct answer.
Detailed Explanation
Q = ωτ, where τ is the time constant for energy decay. τ = Q/ω = Q/(2πf) = 8000/(2π × 600) = 8000/3769.9 = 2.122 s.
Hint
Q = ωτ.