Question Detail
Question
The emission spectrum of gold shows a line of wavelength 2.676 × 10⁻⁷ m. How much energy is emitted as the excited electron falls to the lower energy level?
Correct Answer
Option A is the correct answer.
Detailed Explanation
E = hc/λ = (6.626e-34 × 3e8) / 2.676e-7 = 1.9878e-25 / 2.676e-7 = 7.428 × 10⁻¹⁹ J.
Hint
Use E = hc/λ.