Question Detail
Question
What is the width of a single slit through which 610-nm orange light passes to form a first diffraction minimum at an angle of 30°?
Correct Answer
Option D is the correct answer.
Detailed Explanation
For a single slit, the first minimum occurs at a sin θ = λ. a = λ / sin θ = 610e-9 / sin 30° = 610e-9 / 0.5 = 1.22 × 10⁻⁶ m = 1.22 µm.
Hint
Use a sin θ = λ for the first minimum.