Question Detail
Question
An X-ray beam with a wavelength of exactly 5.00 × 10⁻¹⁴ m strikes a proton that is at rest (m = 1.67 × 10⁻²⁷ kg). If the X-rays are scattered through an angle of 110°, what is the wavelength of the scattered X-rays?
Correct Answer
Option A is the correct answer.
Detailed Explanation
Δλ = (h/(m_p c))(1 - cos θ) = (6.626e-34/(1.67e-27 × 3e8))(1 - cos 110°) = (1.322e-15)(1 - (-0.342)) = 1.322e-15 × 1.342 = 1.774e-15 m. λ' = λ + Δλ = 5.00e-14 + 1.774e-15 = 5.1774e-14 m ≈ 5.18 × 10⁻¹⁴ m.
Hint
Use the Compton scattering formula for scattering off a proton.