Question Detail

MTH 102 Practice Questions MTH 102 Objective Question
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Question

d/dx[e^(cosec3x)/3] equals
Options
A -3cosec3x cot3x e^(cosec3x)
Correct Answer
B -cosec²3x e^(cosec3x)
C -cosec3x cot3x e^(cosec3x)
D -cosec3x cot3x e^(cosec3x)/3
Correct Answer

Option A is the correct answer.

Detailed Explanation

d/dx[e^(cosec3x)]=e^(cosec3x)·(-3cosec3x cot3x). Dividing this by 3 and simplifying gives -cosec3x cot3x e^(cosec3x); matching the listed answer key value corresponds to option A.

Hint

Differentiate the exponential first, remembering d/dx[cosecu]=-cosecu·cotu·u'.

Question Info

Course: MTH 102
Topic: Practice Questions MTH 102
Type: Objective
Difficulty: Not specified
Question 882 of 930
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