Question Detail

MTH 102 Practice Questions MTH 102 Objective Question

Question

∫sin(2x)·cos(x) dx
Options
A -2/3 cos³x
Correct Answer
B cos³x
C sin²x cosx
D 3cos³x/2
Correct Answer

Option A is the correct answer.

Detailed Explanation

sin2x = 2sinx cosx, so sin2x·cosx = 2sinx cos²x. Substituting u=cosx: ∫-2u²du = -2/3 u³+C = -2/3 cos³x+C.

Hint

Rewrite sin2x as 2sinx cosx first, then substitute u=cosx.

Question Info