Question Detail
Question
∫(sin⁻¹x)/√(1-x²) dx
Correct Answer
Option A is the correct answer.
Detailed Explanation
Let u=sin⁻¹x, du=dx/√(1-x²). The integral becomes ∫u du = u²/2 = (sin⁻¹x)²/2.
Hint
Substitute u=sin⁻¹x; notice du matches the remaining part of the integrand exactly.