Question Detail
Question
∫dx/[(sin⁻¹x)√(1-x²)]
Correct Answer
Option B is the correct answer.
Detailed Explanation
Let u=sin⁻¹x, du=dx/√(1-x²). The integral becomes ∫du/u = ln|u| = ln|sin⁻¹x|.
Hint
Substitute u=sin⁻¹x so the remaining factor du/dx cancels the square root.