Question Detail

MTH 102 Practice Questions MTH 102 Objective Question
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Question

∫x/(1+8x²)² dx
Options
A -(1+8x²)/16
B ln|1+4x²|
C -1/[16(1+8x²)]
Correct Answer
D 3/[2(1+8x²)³]
Correct Answer

Option C is the correct answer.

Detailed Explanation

Let u=1+8x², du=16x dx. The integral becomes (1/16)∫u⁻²du = -1/(16u)+C = -1/[16(1+8x²)]+C.

Hint

Substitute u=1+8x², noting du matches x dx up to a constant factor.

Question Info

Course: MTH 102
Topic: Practice Questions MTH 102
Type: Objective
Difficulty: Not specified
Question 886 of 930
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