Question Detail

MTH 102 Practice Questions MTH 102 Objective Question
Take CBT

Question

Given f(x,y)=3tanx·log_ey - y²e^(3x), compute f_yy(x,y)
Options
A 3tanx/y - 2ye^(3x)
B 6log_ey sec²x tanx-9y²e^(3x)
C 3sec²x log_ey-3y²e^(3x)
D -3tanx/y² - 2e^(3x)
Correct Answer
Correct Answer

Option D is the correct answer.

Detailed Explanation

Differentiate f_y=3tanx/y-2ye^(3x) again with respect to y: d/dy[3tanx/y]=-3tanx/y², and d/dy[-2ye^(3x)]=-2e^(3x). Summing gives -3tanx/y²-2e^(3x).

Hint

Differentiate f_y once more with respect to y.

Question Info

Course: MTH 102
Topic: Practice Questions MTH 102
Type: Objective
Difficulty: Not specified
Question 910 of 930
Previous Course Details Next