Question Detail

MTH 102 Practice Questions MTH 102 Objective Question
Take CBT

Question

Given f(x,y)=3tanx·log_ey - y²e^(3x), compute f_xy(x,y)
Options
A 3sec²x/y - 6ye^(3x)
Correct Answer
B 6log_ey sec²x tanx-9y²e^(3x)
C 3sec²x log_ey-3y²e^(3x)
D -3tanx/y² - 2e^(3x)
Correct Answer

Option A is the correct answer.

Detailed Explanation

Differentiate f_x=3sec²x lny-3y²e^(3x) with respect to y: d/dy[3sec²x lny]=3sec²x/y, and d/dy[-3y²e^(3x)]=-6ye^(3x). Summing gives 3sec²x/y - 6ye^(3x).

Hint

Take f_x and differentiate with respect to y this time (mixed partial).

Question Info

Course: MTH 102
Topic: Practice Questions MTH 102
Type: Objective
Difficulty: Not specified
Question 911 of 930
Previous Course Details Next