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MTH 102 Practice Questions MTH 102 Objective Question

Question

Using first principle, evaluate Δy/Δx of the derivative of cos(3x)
Options
A [-sin(3x+3Δx/2)sin(3Δx/2)]/Δx
B [-2cos(3x+3Δx/2)sin(3Δx/2)]/Δx
C [-2sin(3x+3Δx/2)sin(3Δx/2)]/Δx
Correct Answer
D None of the above
Correct Answer

Option C is the correct answer.

Detailed Explanation

Using cosA-cosB=-2sin((A+B)/2)sin((A-B)/2) with A=3(x+Δx), B=3x: Δy=cos3(x+Δx)-cos3x=-2sin(3x+3Δx/2)sin(3Δx/2). Dividing by Δx gives option C.

Hint

Apply the sum-to-product identity for the difference of two cosines.

Question Info