Question Detail
Question
A piece of wood of density 706 kg/m³ is tied to the bottom of a water-filled flask and completely immersed. The volume is 8.0 × 10⁻6 m³. Find the tension in the string. (ρ water = 1000 kg/m³, g = 9.8 m/s²)
Correct Answer
Option B is the correct answer.
Detailed Explanation
Buoyant force = ρwVg = 1000×8×10⁻6×9.8 = 0.0784 N. Weight = 706×8×10⁻6×9.8 = 0.0553 N. Tension = 0.0784 − 0.0553 = 0.023 N.
Hint
Use Archimedes’ principle.