Question Detail

CHM 101 Errors and Stoichiometry Objective Question
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Question

What is the percentage of manganese in KMnO₄? (Molar mass = 158 g, Mn = 54.9 g)
Options
A 24.7%
B 34.8%
Correct Answer
C 40.5%
D 54.9%
Correct Answer

Option B is the correct answer.

Detailed Explanation

% Mn = (54.9 g / 158 g) × 100 = 34.8%.

Hint

The notes provide this percentage.

Question Info

Course: CHM 101
Topic: Errors and Stoichiometry
Type: Objective
Difficulty: Not specified
Question 593 of 1872
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