Question Detail

CHM 101 Errors and Stoichiometry Objective Question
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Question

What is the percentage of oxygen in KMnO₄? (Molar mass = 158 g, O₄ = 64.0 g)
Options
A 24.7%
B 34.8%
C 40.5%
Correct Answer
D 64.0%
Correct Answer

Option C is the correct answer.

Detailed Explanation

% O = (64.0 g / 158 g) × 100 = 40.5%.

Hint

The notes provide this percentage.

Question Info

Course: CHM 101
Topic: Errors and Stoichiometry
Type: Objective
Difficulty: Not specified
Question 594 of 1872
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