Question Detail
Question
In Example 7(a), with no friction, what is the speed of the crate at the bottom of the ramp?
Correct Answer
Option C is the correct answer.
Detailed Explanation
Using energy conservation: mgy_i = ½mv_f². y_i = d sin30° = 1 m × 0.5 = 0.5 m. So v_f = √(2gy_i) = √(2×9.8×0.5) = √9.8 ≈ 3.1 m/s.
Hint
Potential energy at the top becomes kinetic energy at the bottom.