Question Detail
Question
In Example 7(b), with friction (μ_k = 0.15), what is the speed of the crate at the bottom of the ramp?
Correct Answer
Option B is the correct answer.
Detailed Explanation
Using W_nc = ΔKE + ΔPE. The work done by friction is -μ_k mg cosθ d. So -μ_k mg d cosθ = ½mv_f² - mgy_i. Solving for v_f: v_f = √(2g(y_i - μ_k d cosθ)) = √(2×9.8×(0.5 - 0.15×1×0.866)) = √(19.6×0.37) = √7.25 ≈ 2.7 m/s.
Hint
Friction does negative work, reducing the final kinetic energy.