Question Detail

PHY 101 Mechanical Equilibrium and Rotational Dynamics Objective Question

Question

A force of 150 N is applied perpendicularly to the end of a spanner, 0.3 m from the centre of a nut. What is the moment (torque) produced about the centre of the nut?
Options
A 5 Nm
B 45 Nm
Correct Answer
C 50 Nm
D 450 Nm
Correct Answer

Option B is the correct answer.

Detailed Explanation

The moment of a force is calculated as the product of the force and the perpendicular distance from the point of rotation to the line of action of the force. Here, the force is perpendicular, so the distance is the lever arm. Torque = Force × Perpendicular Distance = 150 N × 0.3 m = 45 Nm.

Hint

Recall the formula for moment: τ = F × d, where d is the perpendicular distance.

Question Info