Question Detail

PHY 101 Mechanical Equilibrium and Rotational Dynamics Objective Question
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Question

What is the torque about the centre of a drum with a diameter of 40 cm when a force of 200 N is exerted on a cable wrapped around it?
Options
A 40 Nm
Correct Answer
B 80 Nm
C 4000 Nm
D 8000 Nm
Correct Answer

Option A is the correct answer.

Detailed Explanation

The radius of the drum is half of its diameter, so r = 40 cm / 2 = 20 cm = 0.2 m. The torque is the force multiplied by this radius (the perpendicular distance from the centre to the cable's line of action). Therefore, τ = 200 N × 0.2 m = 40 Nm.

Hint

Remember to use the radius, not the diameter, in the torque calculation. Convert units to meters for standard Nm units.

Question Info

Course: PHY 101
Topic: Mechanical Equilibrium and Rotational Dynamics
Type: Objective
Difficulty: Not specified
Question 563 of 1250
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