Question Detail

PHY 101 Rigid Body Dynamics Objective Question

Question

For a particle in uniform circular motion of radius r with constant angular speed ω, the magnitude of its angular momentum about the center is given by which expression?
Options
A m r ω
B m r² ω
Correct Answer
C ½ m r² ω
D m v / r
Correct Answer

Option B is the correct answer.

Detailed Explanation

For a particle in circular motion, the position vector r (from the center) and the linear momentum p (tangential) are perpendicular. Thus, the magnitude of angular momentum L = r p sin 90° = r p = r (m v). Since v = ω r for circular motion, substituting gives L = r m (ω r) = m r² ω.

Hint

Start with the definition L = r p for the perpendicular case, then relate the linear speed v to angular speed ω.

Question Info