Question Detail

PHY 101 Rigid Body Dynamics Objective Question

Question

If the angular speed ω of a particle in circular motion is not constant (non-uniform circular motion), how is the torque related to its moment of inertia I and angular acceleration α?
Options
A τ = I α
B τ = I ω
C τ = ½ I ω²
D τ = d(Iω)/dt = I α (if I is constant)
Correct Answer
Correct Answer

Option D is the correct answer.

Detailed Explanation

Torque is the rate of change of angular momentum: τ = dL/dt. For a particle in circular motion, L = m r² ω = I ω. Taking the time derivative, and assuming the radius r (and thus I) is constant, gives τ = d(Iω)/dt = I (dω/dt) = I α. This is the rotational analogue of F = m a.

Hint

Relate torque to the time derivative of angular momentum, and then express angular momentum in terms of moment of inertia and angular velocity.

Question Info