Question Detail
Question
A 25.5 mL aliquot of HCl (aq) of unknown concentration was titrated with 51.2 mL of 0.113 M NaOH (aq) to the end point. What is the concentration of the HCl solution?
Correct Answer
Option D is the correct answer.
Detailed Explanation
The reaction is HCl + NaOH → NaCl + H₂O. The mole ratio is 1:1. Moles of NaOH = volume (L) × concentration = (0.0512 L) × (0.113 M) = 0.0057856 mol. Moles of HCl = 0.0057856 mol. Concentration of HCl = moles / volume (L) = 0.0057856 mol / 0.0255 L = 0.2269 M ≈ 0.227 M.
Hint
Use the titration formula: M₁V₁ = M₂V₂ for a 1:1 reaction.